Question

the two diaginals of a rhombus are 20cm and 21 cm.
Find its perimeter.
NO SPAM!!!​

Answer 1

Answer ⬇️

Let ABCD be the rhombus.

AC = 20 cm and BD = 21 cm

We know that the diagonals of a rhombus bisect at right angles.

So, AO = OC = 10 cm

And BO = OD = 10.5 cm

In ΔAOB,

AO^2 + OB^2 = AB^2`

=> 10^2 + 10.5 ^2 = AB^2`

=> 100 + 110.25 = AB^2`

=> AB^2 = 210.25`

=> AB = 14.5 "cm" `

Thus, each side of rhombus = 14.5 cm

Perimeter

= AB + BC + CD + DA

= 14.5 + 14.5 + 14.5 + 14.5

= 58 cm.

$hope \: it \: helps \: uh \:$

Answer 2

Step-by-step explanation:

P=4a

a=p2+q2

2

Solving forP

P=2p2+q2=2·202+212=58cm