Math, asked by Arrush, 10 months ago

The two diagonals of a parallelogram divide it into 4 triangles of equal area.Prove it

Answers

Answered by sameereducation50

We will prove it in next 5 hours

Arrush: Please answer my question...

Answered by Anonymous

given- ABCD is a ||gm(parallelogram)

To prove - ΔADB ≅ ΔCBD

Proof-

as ABCD is a || gm, AD || BC

∴∠ABD = ∠CBD(alternate.interior.∠s)

also AB || DC

∴∠ABD = ∠ CDB(alternate.interior.∠s)

DB = BD(common)

∴ΔADB ≅ ΔCBD

∴ar(ADB) =ar(CBD)

Mark as brainliest

Arrush: I'm really sorry to say that you didn't understand the question well...

Arrush: My question is if you take ||gram ABCD and make the diagonals AC and BD the four triangles will be AOB,BOC,COD and AOD if you take O as the intersection point.You'll have to prove that these triangles have equal area

Anonymous: oh I didn't get it so sorry mate

Arrush: no problem

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