Question

The two diagonals of a rhombus are 20 and 21 cm find its perimeter​

Answer 1

Diagonals of rhombus are 20 CM and 21 CM respectively then find the side an

Diagonals of rhombus are 20 CM and 21 CM respectively then find the side and perimeter of rhombus

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A)

We know that in a rhombus the diagonals bisect each other at 90

so let AC=20 AND BD=21 CM

AD=10 AND BO=10.5 CM

AB^2=AD^2+OB^2

=10^2+10.5^2

=100+110.25

=210.25

AB=14.5 IS THE SIDE OF THE RHOMBUS

PRIMETER=4S

=4(14.5)

=58 CM

Answer 2

perimeter of a rhombus = 2× root diagonal +diagonal

= 2×root 20+21

=2x root 41

value of root 41 is approximately 6.403

so the perimeter of the rhombus =2×6.403

=12.806cm

therefore the perimeter of a rhombus whose diagonals are of length 20and 21 is approximately 12.806cm