Question

The two diagonals of a rhombus are at the ratio 3:5 and area is 9720m², find the two diagonals.. Irrevlant answers will be reported...​

Answer 1

Answer:

Let ABCD be the rhombus with B and D as obtuse angles and perpendicular from D meets AB at E. 

Let diagonals AC and BD meet O.

Both △AOB and ΔDEB are right triangles (as perpendicular of a rhombus bisect each other at right angles and DE is perpendicular on the side AB also angle B is common to both.

Therefore, △AOB∼ΔDEB

⇒DEAO=EBOB=DBAB      .....CPST

∴DE(p)=AO×ABDB

As △AOB is right angled, AB=AO2+BO2=273

Hence, p=(255)×27348=36.164

⇒36cm<p<37cm

Step-by-step explanation:

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Answer 2

solution ⤵️

one diagonal is 3x m and other diagonal is 5x m

area of a rhombus =diagonal 1 ×diagonal 2

area of a rhombus =9720 m²

3X×5X=9720

or,15x²=9720

or,x²=9720/15

or,x²=648

or,√x²=√648

or,x=√648

or,x=25.45

one diagonal =25.45×3=76.35m

other diagonal=25.45×5=127.25m

area of a rhombus=d1×d2

✯rhombus ✯

rhombus is a parallelogram whose adjacent sides are equal