Question

The two diagonals of a rhombus are respectively, 14 cm and 48 cm. The perimeter of the rhombus is equal to

Answer 1

Answer:

D1 of rhombus = 48 cm

D2 of rhombus = 14cm

each side = √7^2 + 24^2

= √49 + 576

= √625

= √25×25

= 25 cm

Perimeter = 25 × 4

= 100 cm

Ans...

Answer 2

The perimeter of the rhombus is 100 cm

Step-by-step explanation:

here ,

the  one  diagonal of the rhombus be p = 14 cm

another diagonal of the rhombus be q = 48 cm

then

perimeter of rhombus = 4a

where

a = $\frac{\sqrt{p^2+q^2} }{2}$

solving for perimeter we get

$P = 2\sqrt{p^2+q^2}$

$P = 2\sqrt{14^2+48^2}$

$P = 2\sqrt{196+2304}\\\\ P = 2\sqrt{2500}\\\\P= 2\times 50\\\\P= 100$

hence , The perimeter of the rhombus is 100 cm

#Learn more:

The diagonal of rhombus are 48 cm and 20 cm long.find the area of rhombus and perimeter of rhombus

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