Question

The two diagonals of a rhombus, PR and QS, intersect each other at point O. Prove that PQ² + QR² + RS² + PS² = 4( OP² + OQ² ). Please answer if you know​

Answer 1

Your answer is in a picture

hence proved

Please mark brainliest answer…

Answer 2

Answer:

answer for the given problem is given

Step-by-step explanation:

Used concept:-

• In a rhombus the diagonals bi-sect to each other at right angle.

Pythagoras Theorem:-

In a right angled triangle ,"The square of hypotenuse is equal to the sum of the squares of the other two sides".