The two diagonals of a rhombus, PR and QS, intersect each other at point O. Prove that PQ² + QR² + RS² + PS² = 4( OP² + OQ² ). Please answer if you know
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Your answer is in a picture
hence proved
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Answer:
answer for the given problem is given
Step-by-step explanation:
Used concept:-
- In a rhombus the diagonals bi-sect to each other at right angle.
Pythagoras Theorem:-
In a right angled triangle ,"The square of hypotenuse is equal to the sum of the squares of the other two sides".
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