Question

the two dice are numbered 123456 and 112233 respectively. they throw and the sum of numbers on them is noted. find the probability of getting each sum from 2 to 9 seperately​

Answer 1

Step-by-step explanation:

The possible outcomes are 36,and they are

1. 1. 2. 2. 3. 3.

1. 1,1 1,1 1,2 1,2 1,3 1,3

2. 2,1 2,1 2,2 2,2 2,3 2,3

3. 3,1 3,1 3,2 3,2 3,3 3,3

4. 4,1 4,1 4,2 4,2 4,3 4,3

5. 5,1 5,1 5,2 5,2 5,3 5,3

6. 6,1 6,1 6,2 6,2 6,3 6,3

Probability=no. Of possible outcomes /total no. Of outcomes

No. Of possible outcomes of getting sum as 2=

2/36=1/18

No. Of possible outcomes of getting sum as 3=

4/36=1/9

No. Of possible outcomes of getting sum as 4=

6/36=1/6

No. Of possible outcomes of getting sum as 5=

6/36=1/6

No. Of possible outcomes of getting sum as 6=

6/36=1/6

No. Of possible outcomes of getting sum as 7=

6/36=1/6

No. Of possible outcomes of getting sum as 8=

4/36=1/9

No. Of possible outcomes of getting sum as 9=

2/36=1/9