Question

the two digit number is 2 more than 5 times th sum of its digit.if the digit in the tens place is 1 less than the digit ih the units place,find the number

Answer 1

Answer:

67

Step-by-step explanation:

let the number in tens place be x

let the number in unit place be y

$10x + y = 5(x + y) + 2 \\ 10x + y = 5x + 5y + 2 \\ 10x + y - 5x - 5y = 2 \\ 5x - 4y = 2 \: \: \: \: \: \: \: equ(1) \\ \\ given \: that \: x = y - 1 \\ x - y = - 1 \\ multiply \: with \: 5 \: we \: get \\ 5x - 5y = - 5 \: \: \: \: equ(2) \\ \\ subtracting \: (1) - (2) \\ y = 7 \\ x = y - 1 \\ x = 7 - 1 \\ x = 6 \\ the \: number \: is \\ = 10x + y \\ = 10(6) + 7 \\ = 60 + 7 \\ = 67$