the two digit number is such that its 10 digit is 6 more than the unit digit also the 3 digit is three times the unit digit find the number
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Step-by-step explanation:
Let the unit digit be = y
Let the tens digit be = x
First equation,
⇒ x = y + 6
Second equation,
⇒ x = 3y
Substitute both equation into each other,
⇒ y + 6 = 3y
⇒ 6 = 2y
⇒ y = 3
Now for the value of x,
⇒ x = y + 6
⇒ x = 3 + 6
⇒ x = 9
Thus, the one's digit is 3 and the tens digit is 9. The number will be 93. I hope I explained well.
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