Question

the two digit number is such that the sum of its digit is 12 and the ones digit is twice its tens digit find the number

Answer 1

let the no. be 10x+y

Now,

x+y=12
x=12-y

y=2x

y=2(12-y)
y=24-2y
3y=12
y=4

x=12-y
=12-4=8

Hence,the required no. is (10×8)+4=80+4=84

So,no is 84

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Answer 2

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