the two digit number is such that the sum of its digit is 4 if it is added to the number its digits are reserved find the number
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Hey Mate!!
Let the digits be x and y
Then the two-digit number is 10x + y
Given that: 10x + y = 4 (x + y)
10x + y = 4x + 4y
6x = 3y
y = 2x --------------- 1
And 10x + y + 18 = 10y + x
Or 9y – 9x = 18 ---------------- 2
Substitute the value of y in eqⁿ 2
18x – 9x = 18
9x = 18
x = 2
Therefore y = 2x = 2 × 2 = 4
And the number is 10x + y = 10 × 2 + 4 = 24
Hence the required number is
Thanks for the question!
Let the digits be x and y
Then the two-digit number is 10x + y
Given that: 10x + y = 4 (x + y)
10x + y = 4x + 4y
6x = 3y
y = 2x --------------- 1
And 10x + y + 18 = 10y + x
Or 9y – 9x = 18 ---------------- 2
Substitute the value of y in eqⁿ 2
18x – 9x = 18
9x = 18
x = 2
Therefore y = 2x = 2 × 2 = 4
And the number is 10x + y = 10 × 2 + 4 = 24
Hence the required number is
Thanks for the question!
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