The two-digit numbers have 6 as a common digit. If the difference between the two numbers is 12 then: one of the numbers is :
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The two-digit numbers have 6 as a common digit. One of the number is 68
Solution:
Given that the difference between the two numbers is 12
The two-digit numbers have 6 as a common digit
Difference of 12 will not be possible if both two digit have 6 at tens place or both two digit have 6 at ones place.
So assuming one number have 6 as digit on tens place and x at ones place
So first number = 6 10 + x = 60 + x
Assuming second number have 6 as digit on ones place and y at ones place
So second number = y 10 + 6 = 10y + 6
given that (60 + x) - (10y + 6) = 12
So for getting 2 in difference at ones place , x – 6 = 2
=> x = 2 + 6 = 8
So one number will be 60 + x = 68.
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