The two digits of two digit number differ by 5 if the digits are reserved the sum of the two numbers is 99 find the numbers
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》》》Let us we assume that: x and y are the two digits of a two-digit number.
Therefore, the two-digit number..
= 10x + y and reversed number = 10y + x
Given:x - y = 5 -------------1
Also given:10x + y + 10y + x
= 9911x + 11y = 99x + y = 9 --------------2
Adding equation 1 and equation22x = 14x = 7
Therefore, y = x - 5 = 7 - 5 = 2Therefore, the two-digit number = 10x + y = 10*7 + 2 = 72
♡♡♡♡if u have any query so tell.me im coment section tnkewww☺☺☺hope help u
》》》Let us we assume that: x and y are the two digits of a two-digit number.
Therefore, the two-digit number..
= 10x + y and reversed number = 10y + x
Given:x - y = 5 -------------1
Also given:10x + y + 10y + x
= 9911x + 11y = 99x + y = 9 --------------2
Adding equation 1 and equation22x = 14x = 7
Therefore, y = x - 5 = 7 - 5 = 2Therefore, the two-digit number = 10x + y = 10*7 + 2 = 72
♡♡♡♡if u have any query so tell.me im coment section tnkewww☺☺☺hope help u
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