Question

the two ends of a train moving with constant acceleration pass a certain point with velocities u and 3u the velocity with which the middle point of the train passes the same point​

Answer 1

HERE IS THE ANSWER

Explanation:

S = (v^2 - u^2) / (2a)

If Length of train is L then

L = ((3u)^2 - u^2) / (2a)

L = 4u^2 / a —-(1)

Midpoint is at Distance L/2

S = (v^2 - u^2) / (2a)

L/2 = (v^2 - u^2) / (2a)

From equation (1)

2u^2 / a = (v^2 - u^2) / (2a)

4u^2 = v^2 - u^2

v^2 = 5u^2

v = u√5

Velocity with which middle point passes the same point is u√5.

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