Question

the two ends of metal rod are maintained at temperatures under degree Celsius and 110 degree Celsius the rate of heat flow in the rod is found to be 4.0 joule per second if this Ends are maintained at temperature 200 degree Celsius and 210 degrees celsius the ratio of heat flow will be ​

Answer 1

Q]___?

=> 4.0 J /s

Explanation

Here,

∆T = 110 - 100 = 10°C

dQ1/dt = 4 J/s => T2 = 210 -200 = 10°C

dQ2/dt = ?

As the rate of heat flow is directly proportional to the temperature difference and the temperature difference in both the cases is same i.e 10°C. So, the same rate of heat will flow in second case hence, dQ2 / dt = 4 J/s

∴The rate of heat flow will be 4 J/s !

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Answer 2

Answer:

♣️The rate of flow of heat is 4J/s..♣️

Explanation:

♥️Hope it will be helpful ☺️ thank you!!♥️