Question

the two equal sides of a right angled isosceles triangle are 10 cm each . Find its area?

Answer 1

area= 1/2 x base x height
since it is right angled isosceles triangle...
area= 1/2 x 10 x 10
        = 50 cm^2

Answer 2

Given:

The two equal sides of a right angled isosceles triangle (a) = 10 cm

We have to find, the area of a right angled isosceles triangle  is:

Solution:

We know that,

The area of a right angled isosceles triangle = $\dfrac{1}{2} a^2$

where, a is the length of the equal sides

∴ The area of a right angled isosceles triangle = $\dfrac{1}{2}\times 10^2 cm^{2}$

= $\dfrac{1}{2}\times 10\times 10 cm^{2}$

= 5 × 10 $cm^{2}$

= 50 $cm^{2}$

∴ The area of a right angled isosceles triangle = 50 $cm^{2}$

Thus, the area of a right angled isosceles triangle is equal to "50 $cm^{2}$".