Question

the two equal sides of a right angled isosceles triangle are 10 cm each . Find its area

Answer 1

area=1/2*b*h
=1/2*10*10=50cm^2...

plzz mark it as a brainliest answer

Answer 2

✬ Area = 50 cm² ✬

Step-by-step explanation:

Given:

• Measure of two equal sides of right isosceles triangle is of 10 cm.

To Find:

• What is the area of ∆?

Solution: Let ABC be a right isosceles triangle in which

• BC = BA = 10 cm
• ∠ABC = 90°

Since, it is a right isosceles triangle therefore its area will be

★ Area of ∆ = 1/2 (Base) (Height) ★

$\implies{\rm }$ 1/2 $\times$ (BC) $\times$ (BA)

$\implies{\rm }$ 1/2 $\times$ (10) $\times$ (10)

$\implies{\rm }$ 5 $\times$ 10

$\implies{\rm }$ 50 cm²

Hence, the area of right isosceles triangle is 50 cm².

_______________

• If opposite sides of an isosceles triangle are equal then angles opposite to equal sides will be also equal.