Question

The two factors of the polynomial 9b2 – 16 are

Answer 1

Answer:

$9 {b}^{2} - 16$

${3}^{2} - {4}^{2}$

$using \: identity \: = > {a}^{2} - {b}^{2} = (a + b)(a - b)$

$(3 + 4)(3 - 4)$

$= 7 \times ( - 1)$

$ans = - 7$

Hope it helps

Answer 2

Step-by-step explanation:

9b^2-16=(3b)^2-4^2 (a^2-b^2=(a+b)(a-b))

=(3b-4)(3b+4)

therefore the two factors are(3b+4)(3b-4)