Chemistry, asked by Jacob6249, 11 months ago

The two fine-structure components of a nuclear magnetic resonance transition are observed at chemical shifts of 2.142 and 2.208 in a 300 MHz NMR spectrometer. Calculate the coupling constant.

Answers

Answered by AditiHegde
1

Given:

The two fine-structure components of a nuclear magnetic resonance transition are observed at chemical shifts of 2.142 and 2.208 in a 300 MHz NMR spectrometer.  

To find:

Calculate the coupling constant.

Solution:

From given, we have,

The chemical shifts of 2.142 and 2.208

300 MHz NMR spectrometer

We use the formula,

Coupling constant (J) = distance between peaks (ppm) * Frequency of NMR Spectrometer (MHz)

= (2.208 - 2.142) × 300

= 0.066 × 300

= 19.8 J

Hence the required coupling constant.

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