The two fine-structure components of a nuclear magnetic resonance transition are observed at chemical shifts of 2.142 and 2.208 in a 300 MHz NMR spectrometer. Calculate the coupling constant.
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Given:
The two fine-structure components of a nuclear magnetic resonance transition are observed at chemical shifts of 2.142 and 2.208 in a 300 MHz NMR spectrometer.
To find:
Calculate the coupling constant.
Solution:
From given, we have,
The chemical shifts of 2.142 and 2.208
300 MHz NMR spectrometer
We use the formula,
Coupling constant (J) = distance between peaks (ppm) * Frequency of NMR Spectrometer (MHz)
= (2.208 - 2.142) × 300
= 0.066 × 300
= 19.8 J
Hence the required coupling constant.
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