Math, asked by Yuktadimpu, 1 year ago

The two harmonic means between 5 and 10


Anonymous: solution :
harmonic mean of 5 and 10 is calculated as follows
= 2 / 1/5 + 1/10
= 2/0.2+0.1
= 2/0.3
= 2/3/10
= 2 *10/3
= 20/3
is this the answer !!!

Answers

Answered by Anonymous
1
 2 / 1/5 + 1/10
= 2/0.2+0.1
= 2/0.3
= 2/3/10
= 2 *10/3
= 20/3
Answered by Yashraj2022sl
0

Answer:

Therefore,  H_{1} = 6 and H_{2} = \frac{15}{2} the two harmonic means between 5 and 10.

Step-by-step explanation:

Insert two HM  between 5 and  10

Let , a = 5  and  b = 10

And  H_{1} and H_{2} be the two  HM

\frac{1}{5}, \frac{1}{H_{1} }  ,\frac{1}{H_{2} }, \frac{1}{10} are in AP , where d is the common difference of this in AP

\frac{1}{10}= (n+2)^{th}term = T_{n+2}

\frac{1}{10} = \frac{1}{5}  + ((n + 2 )- 1)d\\d = \frac{\frac{1}{10}-\frac{1}{5}  }{n+1}

For n = 2, (already given)

d=\frac{\frac{1}{10}-\frac{1}{5}  }{3} = \frac{1-2}{10 X 3 } = \frac{-1}{30}

T_{2} = \frac{1}{5}+ (2-1)×\frac{-1}{30} = \frac{6-1}{30} = \frac{5}{30} = \frac{1}{6} = \frac{1}{H_{1} }

T_{3} = \frac{1}{5} + (2×\frac{-1}{30}) \frac{3-1}{15} = \frac{2}{15} = \frac{1}{H_{2} }

Therefore,  H_{1} = 6 and H_{2} = \frac{15}{2} the two harmonic means between 5 and 10.

#SPJ2

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