Question

The two interior opposite angles of an exterior angle of a triangle are 490 and 410. Find the measure of the exterior angle.
Help pls I’m writing my exam pls have mercy

Answer 1

Step-by-step explanation:

Interior Angeles are 49° and 41°.

$\tt\red{\implies\because [Exterior \:\:angle ]=[sum\: of \:\:interior \:\:opposite\:\: angles]}$

$\tt\pink{\implies \therefore [Exterior\:\: angle ]=49°+41°=90°}$

Answer 2

Given,

Two interior angles of a triangle are $49^{0}$ and $41^{0}$.

The above two interior angles are opposite angles of an exterior angle.

We know that, exterior angle of a triangle is equal to the sum of it's opposite interior angles of a triangle.

So, exterior angle $=49^{0} +41^{0}$

$=90^{0}$.

Hence, the measure of the exterior angle of the given triangle is $90^{0}$.