Question

the two irrational number whose product is a rational number , is ​

Answer 1

$\sqrt{2} \: \times \sqrt{2 } = 2$

and many more irrational numbers in this form are having their product as a rational number

Answer 2

Answer:

$\sf \red{the \: number \: are : }$

$\sf \purple{\sqrt{8 } \: and \: \sqrt{2}}$

$\sf \bf \red{their \: product = }$

$\sqrt{8} \times \sqrt{2} \: = 2 \sqrt{2} \times \sqrt{2 = } \\ 2 \times 2 = 4$

$\bf \tt{it \: is \: a \: rational \: number}$