The two isosceles
right-angle triangles
shown in the figure
are similar triangles.
If the ratio of the
area of the triangles
is 1:3, what is X in
cm?
36 cm
Answers
Step-by-step explanation:
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Answer:
10th
Maths
Triangles
Criteria for Triangle Similarity
Two isosceles triangles hav...
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Asked on December 26, 2019 by
Roshna Varshney
Two isosceles triangles have equal vertical angles and their areas are in the ratio 9:16. Find the ratio of their corresponding heights.
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ANSWER
Let ABC,PQR be two isosceles triangle with equal vertical angles.
Let in ΔABC,AB=AC
⇒∠B=∠C=
2
180−∠A
And in ΔPQR,PQ=PR
⇒∠Q=∠R=
2
180−∠P
Given two vertical angles are equal.
∴∠A=∠P
⇒∠B=∠C=∠Q=∠R
By AAA postulate, "two triangles are similar if they have three corresponding angles congruent."
∴ΔABC∼ΔPQR
We know ratio between the areas of two similar triangles is same as the ration between the squares of their corresponding altitudes and corresponding heights of two given triangles are AD and PS.
AreaofΔPQR
AreaofΔABC
=
PS
2
AD
2
⇒
16
9
=
PS
2
AD
2
⇒AD:PS=3:4