the two legs of a right triangle are sin........-refer image
please give hint
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3π/2 = 270°
sin@ +sin(270-@) = sin@ - cos@
cos@-cos(270-@) = sin@ + cos@
(Length of Hypotenuse= ^2 = (sin@+cos@)^2 + (sin@-cos@)^2
= 2(sin^2@ + cos^2@) = 2×1 = 2
Hence , length of Hypotenuse = √2
sin@ +sin(270-@) = sin@ - cos@
cos@-cos(270-@) = sin@ + cos@
(Length of Hypotenuse= ^2 = (sin@+cos@)^2 + (sin@-cos@)^2
= 2(sin^2@ + cos^2@) = 2×1 = 2
Hence , length of Hypotenuse = √2
Pranshujayswal:
bro but ans is root2
ok i got it
Sorry , that's my fault!
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