The two lines 2x +y-6=0 and 4x – 2y—4=0 intersect at
Answers
Step-by-step explanation:
Refer the attached graph below.
Step-by-step explanation:
Given : 2x+y-6=02x+y−6=0 and 4x-2y-4=04x−2y−4=0
To find : Graph of the equations?
Solution :
Let, Equation 1 - 2x+y-6=02x+y−6=0
and Equation 2- 4x-2y-4=04x−2y−4=0
Now, We find the x and y intercepts of the equation to plot the graph.
Equation 1 - 2x+y-6=02x+y−6=0
Put x=0,
\begin{gathered}2(0)+y-6=0\\y=6\end{gathered}
2(0)+y−6=0
y=6
Put y=0,
\begin{gathered}2x+0-6=0\\x=3\end{gathered}
2x+0−6=0
x=3
Points of equation 1 is (0,6) and (3,0)
Equation 2- 4x-2y-4=04x−2y−4=0
Put x=0,
\begin{gathered}4(0)-2y-4=0\\y=-2\end{gathered}
4(0)−2y−4=0
y=−2
Put y=0,
\begin{gathered}4x-2(0)-4=0\\x=1\end{gathered}
4x−2(0)−4=0
x=1
Points of equation 1 is (0,-2) and (1,0)
Now, we plot these two equations.
The graph of 2x+y-6=02x+y−6=0 is shown with red line.
The graph of 4x-2y-4=04x−2y−4=0 is shown with blue line.
The solution to this system will be their intersection point.
The intersection point of these graph is (2,2)