Question

The two lines lx + my = n and
I'x + m'y = n' are perpendicular if​

Answer 1

Answer:

hai

Step-by-step explanation:

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sorry i do no the ans

Answer 2

Given : two lines lx + my = n and  I'x + m'y = n' are perpendicular  

To find : what is the condition of lines to be perpendicular

Solution :

lx + my = n

=> my  = n - lx

=> y = n/m  - lx/m

=> y = (-l/m)x   + n/m

Slope of line lx + my = n   is   - l/m

l'x + m'y = n'

=> m'y  = n' - l'x

=> y = n'/m'  - l'x/m'

=> y = (-l'/m')x   + n'/m'

Slope of line l'x + m'y = n'   is   - l'/m'

Two line are perpendicular if their slopes multiply to - 1

( - l/m) ( - l'/m')  = - 1

=> ll' = - mm'

=> ll' + mm' = 0

The two lines lx + my = n and  I'x + m'y = n' are perpendicular if​ ll' + mm' = 0

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