Question

The two mixtures A and B contains alcohol and water. Three litres of mixture A and four litres of mixture B are mixed to get a mixture with 30% alcohol. Four litres of mixure A and three litres of mixture B are mixed, we get a mixture with 25% alcohol. In what ratio should we mix the two mixtures A and B to get a new mixture with 27.5% alcohol?​

Answer 1

Step-by-step explanation:

We'll have to mix 8n ratio of 1:1

I'm not sure tho :/

Answer 2

Answer:

1:1

Step-by-step explanation:

let alcohol be x% in A and y% in B.

as given that A nd B are mixed AT 3: 4

we see:

           $\frac{3x+4y}{3+4} = 30$

=> 3x + 4y = 210                                                 .1

similarly, when we mix them in 4: 3 we get

equation 4x+ 3y= 25 * 7 = 175                           .2

now solving .1 and .2

we get, x = 10 and y= 45

now again, we apply same concept as we did to form our above two equations,

     $\frac{10a + 45b}{a+b } = 27.5$

solving this we get a:b as 1:1