Question

the two normals of the circle are x+y-1=0 and x-y+5=0 also area of circle is 4 pi then equation of circle

Answer 1

Answer:

Step-by-step explanation:

2x−3y=5−−−−(1)

3x−4y=7−−−−(2)

are diameter of circle so, point of intersection is centre of circle.

from (1) & (2), x=1,y=−1

∴ area of circle is 154

=πr  

2

=154

r  

2

=  

22

7

​  

×154

=  

2

7×14

​  

 

r  

2

=49

r=7

∴ Equation of circle with centre (1,−1) and radius 7 units

(x−1)  

2

+(y+1)  

2

=7  

2

 

⇒x  

2

+y  

2

−2x+2y−47=0