Question

the two numbers which HCF is 310 and LCM is 1860 the number are​

Answer 1

Answer:

according to the question

ab = 310 X 1860

and the two numbers are 310 and 1860 whose hcf is 310 and lcm is 1860.

Mark me the brainiest please.

Answer 2

Answer:

Either the numbers are (310 and 1860) or (620 and 930).

Step-by-step explanation:

We are given,

HCF = 310

LCM = 1860

Let the two numbers be 310a and 310b where a and b are coprimes.

Coprimes are numbers that have a common factor of 1 only.

Now, you might think why I took 310a and 310b instead of just a and b,

We said that, a and b are coprimes which means If we take the HCF of a and b = 1

But we need 2 numbers whose HCF = 310, thus I took 310a and 310b, now their only common factor is 310 and 1

So HCF = 310

We know that,

Product of 2 numbers = HCF × LCM

then,

310a × 310b = 310 × 1860

310 × 310 × a × b = 310 × 1860

ab = (310 × 1860)/(310 × 310)

ab = 1860/310

ab = 6

Now, we must find the values of a and b such that their products = 6

Now, the possible pairs are (1,6) and (2,3)

We don't need to take the reversed order because the number will be the same.

Now,

the possible numbers are 310a and 310b

So,

(310×1) and (310×6) = 310 and 1860

(310×2) and (310×3) = 620 and 930

Thus, there can be 2 sets of numbers when their HCF = 310 and LCM = 1860

Here, 310 and 1860 have HCF = 310 and

LCM = 1860

also, 620 and 930 have HCF = 310 and

LCM = 1860

Thus,

Either the numbers are (310 and 1860) or (620 and 930).

Hope it helped and you understood it........All the best