The two opposite vertices of a square are (1, -6) and (5, 4). Find the coordinates of
the other two vertices.
Answers
Answered by
0
Answer: (-5,4) & (-9,-6)
Step-by-step explanation:
(1,-6) is in quadrant IV while (5,4) is in quadrant I.
Therefore, length of side = 6+4 = 10.
≡, the other two vertices will be
(5-10,4) ( 4 because the other vertices will be on the same row.)
=(-5, 4)
&
(1-10,-6) ( -6 because the other vertices will be on the same row.)
=(-9,-6)
Similar questions