the two owners A and B cell flavoured milk filled to capacity in mom of negligible thickness which are cylindrical in shape with raised hemispherical bottom the marks are 14 cm high and have diameter of 7 cm as shown in given figure both A and B cell flavoured milk at rupees 80 per litre. the dairy owner is is the formula of πr2h to find the volume of milk in the month charges rupees 43.12 for it dary on FB is of the view that the price of actual quantity of milk should be charged.what according to him should be the price of one mug of milk? which value is exhibited by the dairy owner B? ( use π = 22/7)
Answers
Answered by
1
we know that
1 dm = 1 litre
according to question
radius r = 0.7/2 dm
and Height h = 1.4 dm
thus
Volume of mug = pi r^2 h - 2/3 pi r^3
= pi r^2 (h - 2/3 r)
= 22/7 * 0.49/2 (1.4 - 1.4/6)
= 0.898 lit
Cost of 1 lit milk = Rs 80
So cost of 0.898 lit = 80 * 0.898
= 71.86 Rs
1 dm = 1 litre
according to question
radius r = 0.7/2 dm
and Height h = 1.4 dm
thus
Volume of mug = pi r^2 h - 2/3 pi r^3
= pi r^2 (h - 2/3 r)
= 22/7 * 0.49/2 (1.4 - 1.4/6)
= 0.898 lit
Cost of 1 lit milk = Rs 80
So cost of 0.898 lit = 80 * 0.898
= 71.86 Rs
dishu34:
someone other also answer me but his answer is different from your answer..so what i have to do
Answered by
7
Capacity of mug (Actual quantity of milk) = πr2h - 2/3 πr3
= πr2(h - 2r/3)
r = 7/2 and h = 14
Capacity of mug = 2695/6 cm3
Amount dairy owner B should charge for one mug of milk
= 2695/6 × 80/1000
= Rs. 35.93
= πr2(h - 2r/3)
r = 7/2 and h = 14
Capacity of mug = 2695/6 cm3
Amount dairy owner B should charge for one mug of milk
= 2695/6 × 80/1000
= Rs. 35.93
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