Question

The two palm trees are of equal heights and are standing opposite each

other on either side of the river, which is 80 m wide. From a point O

between them on the river the angles of elevation of the top of the trees

are 60° and 30°, respectively. Find the height of the trees and the

distances of the point O from the trees.

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Answer 1

Answer:

From a point P b/w then on road , the angle of elevation of the top of a pole ... Find the heights of the polesand distances of the point P from the poles. ... BC be the 80 m wide road

follow me please please please please please

Answer 2

Answer:

Let BD=river

AB=CD=palm trees=h

BO=x

OD=80-x

In ∆ABO,

Tan60˚=h/x

√3=h/x -----------------------(1)

H=√3x

In ∆CDO,

Tan 30˚=h/(80-x)

1/√3= h/(80-x) ---------------------(2)

Solving (1) and (2), we get

X=20

H=√3x=34.6

the height of the trees=h=34.6m

BO=x=20m

DO=80-x=80-20=60m