The two palm trees are of equal heights and are standing opposite each
other on either side of the river, which is 80 m wide. From a point O
between them on the river the angles of elevation of the top of the trees
are 60° and 30°, respectively. Find the height of the trees and the
distances of the point O from the trees.
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Let Palm tree be poles
tan600=80−xb
⇒3=80−xb
⇒b=3x−803 ....(i)
and,
tan300=31=xa
x=a3 ...(ii)
b=3a−803
Or
3a−b=803
Now it is given that the heights are equal.
Hence
a=b=h
Therefore
2h=803
h=203
=2(17.32)
=34.64m
Hence
x=h3
=20(3)=60m
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