The two palm trees are of equal heights and are standing opposite each
other on either side of the river, which is 80 m wide. From a point O
between them on the river the angles of elevation of the top of the trees
are 60° and 30°, respectively. Find the height of the trees and the
distances of the point O from the trees.
Answers
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Step-by-step explanation:
Let BD = river
AB = CD = palm trees = h
BO = x
OD = 80 - x
In ∆ABO,
tan60˚ = h/x
√3 = h/x---- (1)
H = √3x
In ∆CDO,
tan30˚ = h/80−x
1/√13 = h/80−x--- (2)
Solving (1) and (2), we get
x = 20
H = √3x = 34.6
The height of the trees = h = 34.6m
BO = x = 20m
DO = 80 - x
= 80 - 20 = 60m
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