The two palm trees are of equal heights and are standing opposite each
other on either side of the river, which is 80 m wide. From a point O
between them on the river the angles of elevation of the top of the trees
are 60° and 30°, respectively. Find the height of the trees and the
distances of the point O from the trees.
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Answer:
Let AB and CD aree two trees on two sides of the river
Let their height be h and the distance of the point O from tree AB be x
Consider triangle AOB
tan60 =h/x=√3. This gives h=x√3
Consider triangle DOC
tan30=h/(80-x)= 1/√3. This gives
h√3= 80-x
Put h=x√3 in this equation
x√3×√3 =80-x
3x+x= 80
4x =80
x= 20
h=20√3
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