Math, asked by logic2, 1 year ago

the two parallel sides and the distance between them are in ratio 3:4:2. if the area of the trapezium is 175 cm2 ; find its height.

Answers

Answered by rohan5101
53
hope it helps you. .......
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Answered by Anonymous
35
hii!!

here's ur answer...

let the two parallel sides of the trapezium be 3x and 4x and height be 2x.

area of the trapezium = 175cm²

therefore 1/2×h(b1+b2) = 175cm²

=> 1/2×2x(3x+4x) = 175cm²

=> x×7x = 175cm²

=> 7x² = 175cm²

=> x² = 175/7

=> x² = 25

=> x = √25

=> x = 5

hence parallel sides are 3x and 4x.

→ 3x = 3×5
= 15cm

→ 4x = 4×5
= 20cm

→ height of the trapezium = 2x
= 2×5
= 10cm

VERIFICATION:-

area of the trapezium = 1/2×h(b1+b2)

= 1/2×10(15+20)

= 5×35

= 175cm²

hence verified

hope this helps u..!
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