The two parallel sides of a trapezium are of length 24cm and 30 cm respectively, and the
distance between them are 10 cm. Find the area of the trapezium.
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Answered by
0
Answer:
The length of the non-parallel sides is [24–10–4]/2 = [24–14]/2 = 10/2 = 5 cm each. = 4*7 = 28 sq cm. How do we find the distance between the parallel sides of an isosceles trapezium when the perimeter given is 24 cm and the parallel sides are 10 cm and 4 cm
ANSWER IS 10 CM AND 4CM.
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Answered by
1
Answer:
270sqcm
Step-by-step explanation:
area of trapezium= 1/2*h(a+b) = 1/2*10(24+30) = 5*54 =270sqcm
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