The two plates of a parallel plate capacitor are 4 mm apart. A slab of dielectric
constant 3 and thickness 3 mm is introduced between the plates with its faces parallel to
them. The distance between the plates is so adjusted that the capacitance of the capacitor
becomes 2/3rd of its original value. What is the new distance between the plates? On
charging a parallel plate capacitor to a potential V, the spacing between the plates is halved,
and a dielectric medium of r = 10 is introduced between the plates, without disconnecting
the d.c. source. Explain, using suitable expressions, how the (i) capacitance, (ii) electric field
and (iii) energy density of the capacitor change.
Answers
Answered by
0
in which class are u? not able. to. do. this
Similar questions