Physics, asked by lionsdj64431, 19 days ago

The two plates of a parallel plate capacitor are 4mm apart.A slab of dielectric constant 3 and thickness 3mm is introduced between the plates with its faces parallel to them.the distance between the plates is so adjusted that the capacitance of the capacitor becomes 2/3rd of its original value.what is the new distance between the plates?

Answers

Answered by DGAMER
0

Answer:

2+2=5

Explanation:

2+2=4

4+5=9

9-(2+2)=5

THEREFORE, 2+2=5

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