Question

The two points charges q_1=20 micro coulomb and q_2=25 micro coulomb are placed at (-1,1,1) and(3,-1,-2) with respect to some coordinate axes. The coordinates are in metre. Find the components of the force along three coordinates axes . Also find net magnitude of the force.

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Answer 1

Answer:

Let position vector of q1 is r1 and position vector of q2 is r2

e.g., r1 = (-1, 1, 1) and r2 = (3, 1, -2)

we have to find magnitude and unit vector along force on q2.

so, position vector of q2 with respect to q1 , r = r2 - r1 = (3, 1, -2) - (-1, 1, 1) = (4, 0, -3)

magnitude of r = |r| = √{4² + 0² + (-3)²} = 5

magnitude of force on q2 = kq1q2/|r|²

= 9 × 10^9 × 20 × 10^-6 × 25 × 10^-6 /5²

= 9 × 10^9 × 20 × 10^-12

=0.18 N

now, unit vector along force on q2 = (r2 - r1)/|r2 - r1| = (4, 0, -3)/5 = (0.8, 0, -0.6)

hence, unit vector is (0.8, 0, -0.6).

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