The two possible equivalentinductance (legs of two series.connected coils with self-inductances 0.07H and o.o9H andmutual inductance is 0.01 H are
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0.18H and 0.14H are two possible equivalent inductance if 0.07H and 0.09H connected in series with mutual inductance 0.01 H
Explanation:
Mutually Connected Inductors in Series
L₁ & L₂
Leq = L₁ + L₂ ± 2M
L₁ = 0.07H
L₂ = 0.09 H
M = 0.01 H
Two possible equivalent inductance
L₁ + L₂ + 2M or L₁ + L₂ - 2M
= 0.07 + 0.09 + 2(0.01 ) or 0.07 + 0.09 - 2(0.01 )
= 0.18H or 0.14H
0.18H and 0.14H
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