the two side of a square are given by the expressions 3X+1 and 4x-2 find the perimeter of the square
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3x+1=4x-2
3x is transposed to right it becomes -3x
-2 is transposed to left it becomes 2
=1+2=4x-3x
=3=x
x=3
perimeter of the square is 4x
4x3=12
he perimeter of the square is 12
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3x is transposed to right it becomes -3x
-2 is transposed to left it becomes 2
=1+2=4x-3x
=3=x
x=3
perimeter of the square is 4x
4x3=12
he perimeter of the square is 12
plzzzz mark me as brainliest answer friend
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