The two sides of a right angled triangle containing the right angle are 8cm and 6cm.find the hypotenuse
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10
HEY!!
HERE IS YOUR ANSWER.,,
Let ∆ABC is right angled triangle.
AB^2 + BC^2 = AC^2
AB = 8cm
BC = 6cm
AC^2 = hypotenuse
AC^2 = 8^2 + 6^2
= 64 + 36
= 100
AC = √100
AC = 10 cm
HOPE IT HELP YOU..
THANKS.
HERE IS YOUR ANSWER.,,
Let ∆ABC is right angled triangle.
AB^2 + BC^2 = AC^2
AB = 8cm
BC = 6cm
AC^2 = hypotenuse
AC^2 = 8^2 + 6^2
= 64 + 36
= 100
AC = √100
AC = 10 cm
HOPE IT HELP YOU..
THANKS.
Answered by
2
AB
so 64 +36= ac^2
so AC =10
so 64 +36= ac^2
so AC =10
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