Question

the two sides of a right angled trianglecare 5 cm and 12 cm, find the area as well as the lenght of hypotenuse​

Answer 1

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Let in ∆ABC, BC = 5 cm and AC = 12 cm.

Therefore,

By Pythagoras theorem,

(AB)² = (BC)² + (AC)²

=> (AB)² = (5)² + (12)²

=> (AB)² = 5 × 5 + 12 × 12

=> (AB)² = 25 + 144

=> (AB)² = 169

Now,

(AB)² = 169

AB × AB = 13 × 13

=> Or AB = 13 Cm

Therefore,

• Length of the hypotenuse = 13 cm.

Answer 2

Answer:

13 cm

Step-by-step explanation:

Given

---------

base ( b) be 12 cm and

perpendicular ( p) be 5 cm

and hypotenuse be h

A.T.Q

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$b ^{2} + p ^{2} = h ^{2}$

${12}^{2} + {5}^{2} = h ^{2}$

$144 + 25 = 169$

$\sqrt{169 } = 13$

Hope you get the answer of this question