Question

The two sides of a square are given by the expressions 3x + 1 and 4x – 2. Find the perimeter of the

square​

Answer 1

Given-

• Two sides of square-3x+1 and 4x-2

Concept used-

$\begin{cases} \text{perimeter \: of \: square = 4a } \\ \text{side \: of \: square \: are \: equal}\end{cases}$

Solution-

$\because \bf all \: sides \: of \: square \: are \: equal \\ \therefore \bf 3x + 1 = 4x - 2 \\ \implies \bf 1 + 2 =4x - 3x \\ \implies \underline{\boxed{ \bf x = 3 }}$

$\bf \underline{ side(a) = 3 \times 3 + 1 = 10}$

or

$\bf \underline{ side(a) = 4 \times 3 - 2 = 12 - 2 = 10}$

$\bf \: perimeter \: of \: square = 4 \times side(a) \\ \implies \bf perimeter \: of \: square = 4 \times 10 \\ \underline{ \boxed{ \large \bf \: perimeter \: of \: square = 40}}$

Hence perimeter of square is 40 units