Question

the two sides of a triangle are 3cm and 4 cm and its perimeter is 12 cm. find its area

Answer 1

Answer:

6cm²

Step-by-step explanation:

a= Side

3

cm

b =Base

4

cm

P =Perimeter

12

cm

Using the formulas

A=s(s﹣a)(s﹣b)(s﹣c)

P=a+b+c

s=a+b+c

2

Solving forA

A=1

4﹣P4+4P3a+4P3b﹣4(Pa)2﹣12P2ab﹣4(Pb)2+8Pa2b+8Pab2=1

4·﹣124+4·123·3+4·123·4﹣4·(12·3)2﹣12·122·3·4﹣4·(12·4)2+8·12·32·4+8·12·3·42=6cm²

a Side

3

cm

b Base

4

cm

P Perimeter

12

cm

Using the formulas

A=s(s﹣a)(s﹣b)(s﹣c)

P=a+b+c

s=a+b+c

2

Solving forA

A=1

4﹣P4+4P3a+4P3b﹣4(Pa)2﹣12P2ab﹣4(Pb)2+8Pa2b+8Pab2=1

4·﹣124+4·123·3+4·123·4﹣4·(12·3)2﹣12·122·3·4﹣4·(12·4)2+8·12·32·4+8·12·3·42=6cm²