The two successive natural frequencies of an organ pipe closed at one-end and
open at the other are 700 Hz and 900 Hz respectively. Neglect end correction and
take the speed of sound in air as 320 m/s. The length of the pipe is found to be 10n
cm. Find the value of n.
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Given :
Frequency 1 = 700Hz
Frequency 2 = 900 Hz
Speed of sound in air = 320m/s
To find :
The value of n
Solution:
- we know the relation, f₀ = f₂ - f₁
= 900 - 700 = 200 Hz
- Wavelength = v/f₀
=320/200 = 1.6m
- Length of pipe = wavelength / 2
= 0.8m = 80cm
- From the question 10n = 80
n = 8
The value of n is 8
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