the two supplementary angles differ by 40 Degrees find the measure of each angle
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20
since they differ from 40 degrees therefore the angles are and let the angle be x
=> x+x+40=180=>2x=180-40=>x=140/2=>70
therefore the angles are 70 degrees
and 70+40=110 degrees
=> x+x+40=180=>2x=180-40=>x=140/2=>70
therefore the angles are 70 degrees
and 70+40=110 degrees
dheeraj68:
then mark as brainliest
Answered by
14
the sum of two supplimentary angles = 180 degrees
difference of the two supplimentary angles = 40
two spplimentary angles = x and x + 40
x + x + 40
=2x + 40 = 180
= 2x = 180 - 40 = 140
= x = 140/2 = 70 degrees
angle 1 = x = 70 degrees
angle 2 = x+40 = 70+40 = 110 degrees
thus the two angles are 70 and 110 degrees
difference of the two supplimentary angles = 40
two spplimentary angles = x and x + 40
x + x + 40
=2x + 40 = 180
= 2x = 180 - 40 = 140
= x = 140/2 = 70 degrees
angle 1 = x = 70 degrees
angle 2 = x+40 = 70+40 = 110 degrees
thus the two angles are 70 and 110 degrees
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