Question

The two tangents drawn from an external point p to a circle with center o are PA and PB if angle APB equal 70 what is the value of angle AOB

Answer 1

Here,

We know that sum of all the angles of a quadrilateral= 360°

AOBP= angle OAP+ angle AOB+ angle OBP + angle APB

360° = 90° + angle AOB + 90° + 70°

360° = 250° + angle AOB

360°- 250° = angle AOB

110° = angle AOB

HOPE IT HELPS YOU

Answer 2

Answer:

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