Question

The two thigh bones, each of area 10 cm support
the upper part of a human body of mass 40 kg.
Estimate the total pressure sustained by the both
bones. Apply, formula for weight, W = mx 9.8.


please give me th answer ​

Answer 1

Answer:

Here is the solution

Explanation:

The mass of the upper part is 40kg and the value of g = 10ms−2 . Therefore, F=mg=(40)(10)=400N. Due to this force, the upper part will exert a pressure on the cross section of the femurs. It is given that the area of the cross section of each thigh is 10cm2=10(10−2m)2=10−3m2.

Answer 2

Answer:

The mass of the upper part is 40kg and the value of g = 10ms−2 . Therefore, F=mg=(40)(10)=400N. Due to this force, the upper part will exert a pressure on the cross section of the femurs. It is given that the area of the cross section of each thigh is 10cm2=10(10−2m)2=10−3m2.

Explanation

The two thigh bones (femurs) each of cross-sectional are 10 cm^(2) support the upper part of a human bodu of mass 40 kg . Estimate the average pressure sustained by the femurs. g=10m//s^(2) =2×105Nm-

The femur bone or the thigh bone carries the mass of the body of 40 kg. Solution: The pressure sustained by the femurs is dependent upon the weight and its area of cross sections.